0=-2x^2+16x^2+88x

Solution for 0=-2x^2+16x^2+88x equation:

0=-2x^2+16x^2+88x

We move all terms to the left:

0-(-2x^2+16x^2+88x)=0

We add all the numbers together, and all the variables

-(-2x^2+16x^2+88x)=0

We get rid of parentheses

2x^2-16x^2-88x=0

We add all the numbers together, and all the variables

-14x^2-88x=0

a = -14; b = -88; c = 0;
Δ = b2-4ac
Δ = -882-4·(-14)·0
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88)-88}{2*-14}=\frac{0}{-28}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88)+88}{2*-14}=\frac{176}{-28}
=-6+2/7
$